Physics · Relativity
वेग v से गतिमान विराम द्रव्यमान m0 वाले एक आपेक्षिकीय कण की गतिज ऊर्जा होगी:
- 1m0c2 + 12 m0v2
- 212 m0c2 + 12 m0v2
- 3m0c2√(1 - v2/c2) [1 - √(1 - v2/c2)]✓
- 412 × m0v2√(1 - v2/c2)
सही उत्तर देखें
m0c2√(1 - v2/c2) [1 - √(1 - v2/c2)]
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