Physics · Relativity
The kinetic energy of a relativistic particle with rest mass m0, moving with a velocity v, is given by:
- 112 m0c2 + 12 m0v2
- 2m0c2 + 12 m0v2
- 3m0c2√(1 - v2/c2) [1 - √(1 - v2/c2)]✓
- 412 × m0v2√(1 - v2/c2)
Correct answer
m0c2√(1 - v2/c2) [1 - √(1 - v2/c2)]
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