Mathematics · Partial Differential Equations
मान लीजिए कि u(x, t) प्रारंभिक मान समस्या (initial value problem) ∂2u∂t2 - 9 ∂2u∂x2 = 0, x ∈ ℝ, t > 0 का हल है, जो u(x, 0) = ex और ∂u∂t(x, 0) = sin x को संतुष्ट करता है। तो u(π2, π6) का मान है:
- 112 (eπ - 53)
- 212 (eπ + 53)✓
- 312 (eπ + 13)
- 412 (eπ - 13)
सही उत्तर देखें
12 (eπ + 53)
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