Mathematics · Partial Differential Equations
Let u(x, t) be the solution of the initial value problem ∂2u∂t2 - 9 ∂2u∂x2 = 0, x ∈ ℝ, t > 0, satisfying u(x, 0) = ex and ∂u∂t(x, 0) = sin x. Then, the value of u(π2, π6) is:
- 112 (eπ - 53)
- 212 (eπ + 53)✓
- 312 (eπ + 13)
- 412 (eπ - 13)
Correct answer
12 (eπ + 53)
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