Physics · Quantum Mechanics
एक दो-स्तरीय क्वांटम प्रणाली के लिए हैमिल्टनियन ऑपरेटर H = E100E2 है। यदि t = 0 पर प्रणाली की स्थिति |ψ(0)⟩ = 1√211 द्वारा दी गई है, तो वह न्यूनतम समय t ज्ञात कीजिए जिसके लिए |⟨ψ(0) | ψ(t)⟩|2 = 12 हो।
- 12πℏE1 - E2
- 2πℏE1 - E2
- 3πℏ2(E1 - E2)✓
- 4πℏ4(E1 - E2)
सही उत्तर देखें
πℏ2(E1 - E2)
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