Physics · Quantum Mechanics
A quantum mechanical particle in a harmonic potential has the wave function 1√2 [ψ0(x) + ψ1(x)] at t = 0, where ψ0(x) and ψ1(x) are the ground state and first excited state wave functions respectively. If the oscillator frequency is ω, the probability density of finding the particle at x after time t = πω is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 112 |ψ1(x)|2 + 12 |ψ0(x)|2
- 212 |ψ1(x) - iψ0(x)|2
- 312 |ψ1(x) + ψ0(x)|2
- 412 |ψ1(x) - ψ0(x)|2✓
Correct answer
12 |ψ1(x) - ψ0(x)|2
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