Mathematics · Complex Analysis
Let &mathbb;T denote the unit circle {z ∈ &mathbb;C : |z| = 1} in the complex plane and let &mathbb;D be the open unit disc {z ∈ &mathbb;C : |z| < 1}. Let R denote the set of points z0 in &mathbb;T for which there exists a holomorphic function f in an open neighbourhood Uz0 of z0 such that f(z) = Σn=0∞ z4n in Uz0 ∩ &mathbb;D. Then R contains:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1No points of &mathbb;T✓
- 2All points of &mathbb;T except a finite set
- 3Infinitely many points of &mathbb;T
- 4All points of &mathbb;T
Correct answer
No points of &mathbb;T
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