Mathematics · Linear Algebra
If T: V → V is a linear operator with minimal polynomial f(x) = (x − 1)2, then:
- 1T is non-diagonalizable and the Jordan form of T does not exist
- 2T is non-diagonalizable and it has a Jordan form✓
- 3T is diagonalizable but it does not have a Jordan form
- 4T is diagonalizable and the Jordan form of T exists
Correct answer
T is non-diagonalizable and it has a Jordan form
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Preparing for Mathematics?
Practice full-length Mathematics mock tests with real exam timers, instant score analysis, and all-India ranking.
Want more practice questions on Linear Algebra?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Mathematics · Linear Algebra