Mathematics · Integration
For α, β, γ, δ ∈ &mathbb{N}, if ∫ [ (x/e)2x + (e/x)2x ] logex dx = 1α(x/e)βx - 1γ(e/x)δx + C, where e = ∑n=0∞ 1n! and C is the constant of integration, then α + 2β + 3γ - 4δ is equal to:
- 14✓
- 2-8
- 3-4
- 41
Correct answer
4
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