For the reaction CH3Br(aq) + OH-(aq) → CH3OH(aq) + Br-(aq), the rate law is rate = k[CH3Br][OH-]. By what factor does the rate of reaction change if the concentration of both reactants is doubled?

Match List I (Order of reaction) with List II (Unit of rate constant): List I: A. Zero order B. First order C. Second order D. Third order List II: I. mol-1 L s-1 II. mol-2 L2 s-1 III. s-1 IV. mol L-1 s-1 Choose the correct matching:

Given below is an expression for the rate constant of a first order reaction occurring at a certain temperature, T (K): ln k = 14.34 - 1.25 × 104T The energy of activation in kcal mol-1 for the reaction is: (Given: k in s-1, R = 1.987 cal mol-1 K-1)