Chemistry · Chemical Kinetics
An enzyme (E) catalyzes the conversion of a substrate (S) to product (P) according to the mechanism: E + S ⮈ ES (k1, k-1) → ES' (k2) → E + P (k3) Applying steady state approximation to ES and ES', the expression for the rate of reaction (where [E]0 and [S]0 are initial concentrations and [S]0 >> [E]0) is:
- 1k1k2[E]0[S]0(k-1 + k2) + k2(1 + k1k3)[S]0
- 2k1k2[E]0[S]0(k-1 + k2) + k1(1 + k2k3)[S]0✓
- 3k1k2[E]0[S]0(k-1 + k2) + k1[S]0
- 4k3[E]0[S]0
Correct answer
k1k2[E]0[S]0(k-1 + k2) + k1(1 + k2k3)[S]0
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