Find the temperature T (in kelvin) at which the rate constants are equal for the following two reactions: Testbook + 1 Reaction 1: A → B, where K1 = 104 e−24000/T Reaction 2: P → Q, where K2 = 106 e−30000/T (Take ln 10 = 2.3)

Match List I (Order of reaction) with List II (Unit of rate constant): List I: A. Zero order B. First order C. Second order D. Third order List II: I. mol-1 L s-1 II. mol-2 L2 s-1 III. s-1 IV. mol L-1 s-1 Choose the correct matching:

Given below is an expression for the rate constant of a first order reaction occurring at a certain temperature, T (K): ln k = 14.34 - 1.25 × 104T The energy of activation in kcal mol-1 for the reaction is: (Given: k in s-1, R = 1.987 cal mol-1 K-1)