Physics · Electromagnetic Waves
समानांतर ध्रुवीकरण (parallel polarization) और दोषरहित परावैद्युत (lossless dielectrics) के लिए, माध्यम 1 से माध्यम 2 (क्रमशः परावैद्युतांक ε 1 और ε 2 ) में यात्रा करने वाली विद्युत चुंबकीय तरंग के लिए ब्रूस्टर कोण (θ p ) का व्यंजक क्या है?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1θ p = cos -1 (√( ε 1 ε 2 ))
- 2θ p = tan -1 (√( ε 2 ε 1 ))✓
- 3θ p = sin -1 (√( ε 2 /ε 1 1 + ε 2 /ε 1 ))
- 4θ p = sin -1 (√( ε 1 /ε 2 1 + √(ε 1 /ε 2 ) ))
सही उत्तर देखें
θ p = tan -1 (√( ε 2 ε 1 ))
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