Mathematics · Limits
यदि α और β समीकरण x2 + bx + c = 0 के भिन्न मूल हैं, तो limx → β e2(x2 + bx + c) - 1 - 2(x2 + bx + c)(x - β)2 किसके बराबर है?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1b2 + 4c
- 22(b2 - 4c)✓
- 3b2 - 4c
- 42(b2 + 4c)
सही उत्तर देखें
2(b2 - 4c)
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