Mathematics · Differentiation
यदि y = √(cosh x + √cosh x), तो dydx =
- 1&sinh; x (2y2 + 2&cosh; x + 1)4y(y2 + &cosh; x)
- 2&sinh; x (2y2 - 2&cosh; x - 1)4y(y2 - &cosh; x)
- 3&sinh; x (1 - 2√cosh x)4y√cosh x
- 4&sinh; x (1 + 2√cosh x)4y√cosh x✓
सही उत्तर देखें
&sinh; x (1 + 2√cosh x)4y√cosh x
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