Mathematics · Binomial Theorem
यदि (1 + x)2n के प्रसार में दूसरे, तीसरे और चौथे पदों के गुणांक समांतर श्रेणी (A.P.) में हैं, तो:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 12n2 + 9n - 7 = 0
- 22n2 - 9n - 7 = 0
- 32n2 - 9n + 7 = 0✓
- 42n2 + 9n + 7 = 0
सही उत्तर देखें
2n2 - 9n + 7 = 0
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