Computer Science · Divide and Conquer Complexity
बाइनरी सर्च (Binary Search) की सबसे खराब स्थिति (worst-case) की समय जटिलता के लिए निम्नलिखित में से कौन सा सही पुनरावृत्ति संबंध (recurrence relation) है?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1T(n) = 2T(n/2) + O(1), जहाँ T(1) = T(0) = O(1)
- 2T(n) = T(n/2) + O(n), जहाँ T(1) = T(0) = O(1)
- 3T(n) = T(n/2) + O(1), जहाँ T(1) = T(0) = O(1)✓
- 4T(n) = T(n/2) + O(log n), जहाँ T(1) = T(0) = O(1)
सही उत्तर देखें
T(n) = T(n/2) + O(1), जहाँ T(1) = T(0) = O(1)
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