Computer Science · Analysis of Algorithms
बाइनरी तुलनाओं पर आधारित एक सॉर्टिंग एल्गोरिदम को n तत्वों को सॉर्ट करने के लिए सबसे खराब स्थिति में कम से कम कितनी तुलनाओं की आवश्यकता होती है?
- 1⌈log2(n!)⌉ / n
- 2⌈log2((n-1)!)⌉ / n
- 3⌈log2(n!)⌉✓
- 4⌈log2((n-1)!)⌉
सही उत्तर देखें
⌈log2(n!)⌉
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