Mathematics · Abstract Algebra
- 1f, &mathbb{Z}[√13] पर अखंडनीय (irreducible) है
- 2f, &mathbb{Q;} पर अखंडनीय (irreducible) है✓
- 3f, &mathbb{Q;}[√13] पर खंडनीय (reducible) है
- 4&mathbb{Z}[√13] एक अद्वितीय गुणनखंडन प्रांत (unique factorization domain) है
सही उत्तर देखें
f, &mathbb{Q;} पर अखंडनीय (irreducible) है
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