Computer · Strength of Materials
प्रत्यास्थता मापांक (modulus of elasticity) E = 2.5 × 104 N/mm2 और रोकी गई तापीय विकृति (prevented thermal strain) = 200 × 10-6 वाले पदार्थ के लिए, प्रेरित तापीय प्रतिबल कितना होगा?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 16.0 N/mm2
- 25.0 N/mm2✓
- 34.0 N/mm2
- 43.5 N/mm2
सही उत्तर देखें
5.0 N/mm2
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