Mathematics · Statistics
न्यूनतम महत्वपूर्ण अंतर (LSD) परीक्षण में, महत्वपूर्ण अंतर (CD) की गणना किस सूत्र द्वारा की जाती है?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
Share:
- 1CD = t0.05(error d.f.) √8(MSS)errorn
- 2CD = t0.05(error d.f.) √6(MSS)errorn
- 3CD = t0.05(error d.f.) √4(MSS)errorn
- 4CD = t0.05(error d.f.) √2(MSS)errorn✓
सही उत्तर देखें
CD = t0.05(error d.f.) √2(MSS)errorn
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
👥
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Online Test Series
Preparing for Mathematics?
Practice full-length Mathematics mock tests with real exam timers, instant score analysis, and all-India ranking.
Chapter Practice
Practice Statistics MCQs →Want more practice questions on Statistics?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Mathematics · Statistics