Mathematics · Speed, Time and Distance
दो वाहन एक ही लेन वाली सड़क पर 25 m/s की गति से विपरीत दिशाओं से एक-दूसरे की ओर आ रहे हैं। यदि धारणा-प्रतिक्रिया समय (perception-reaction time) 2.5 s, अनुदैर्ध्य घर्षण गुणांक (coefficient of longitudinal friction) 0.50, ब्रेक दक्षता 50% और गुरुत्वाकर्षण त्वरण 10 m/s2 माना जाए, तो आमने-सामने की टक्कर से बचने के लिए आवश्यक न्यूनतम दूरी कितनी होगी?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
Share:
- 1307.2 m
- 2375.0 m
- 3187.5 m
- 4153.6 m✓
सही उत्तर देखें
153.6 m
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
👥
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Online Test Series
Start Free Mock Test →Preparing for Mathematics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Chapter Practice
Practice Speed, Time and Distance MCQs →Want more practice questions on Speed, Time and Distance?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Mathematics · Speed, Time and Distance