Mathematics · Electromagnetic Induction
दो चुंबकीय रूप से युग्मित कुंडलियों (coils) पर विचार करें जहाँ लूप 1 का स्व-प्रेरकत्व L1 है और लूप 2 में धारा i2(t) के कारण पारस्परिक रूप से प्रेरित वोल्टेज M है। यदि धाराएं दोनों कुंडलियों में डॉटेड टर्मिनलों में प्रवेश करती हैं, तो लूप 1 के लिए अवकल समीकरण (differential equation) क्या होगा?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1V2(t) = L1(di1(t)/dt) + M(di2(t)/dt)
- 2V1(t) = M(di1(t)/dt) + L2(di2(t)/dt)
- 3V1(t) = L1(di1(t)/dt) - M(di2(t)/dt)
- 4V1(t) = L1(di1(t)/dt) + M(di2(t)/dt)✓
सही उत्तर देखें
V1(t) = L1(di1(t)/dt) + M(di2(t)/dt)
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