Physics · Thermodynamics
तीन कार्नोट इंजन E1, E2, और E3 तापमान T1 और T4 के बीच श्रृंखला (series) में काम कर रहे हैं, जिनके मध्यवर्ती तापमान T2 और T3 हैं। इंजन समान रूप से कुशल (equally efficient) होंगे यदि निम्नलिखित में से कौन सा संबंध सत्य है?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1T2 = (T12 T4)2/3 और T3 = T12/3 × T45/6
- 2T2 = (T4 T3)3 और T3 = (T2 T4)3
- 3T2 = (T1 T4)1/3 और T3 = (T1 T4)2/3
- 4T2 = (T12 T4)1/3 और T3 = (T1 T42)1/3✓
सही उत्तर देखें
T2 = (T12 T4)1/3 और T3 = (T1 T42)1/3
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