Mathematics · Taylor's Theorem
टेलर के प्रमेय का उपयोग करके (x - 3π/2) की घातों में sin(x) का विस्तार करें।
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1sin(x) = (x - 3π/2) - (x - 3π/2)33! + (x - 3π/2)55! - ...
- 2sin(x) = 1 + (x - 3π/2)1! + (x - 3π/2)33! - ...
- 3sin(x) = 1 + (x - 3π/2)1! + (x - 3π/2)22! + ...
- 4sin(x) = -1 + (x - 3π/2)22! - (x - 3π/2)44! + ...✓
सही उत्तर देखें
sin(x) = -1 + (x - 3π/2)22! - (x - 3π/2)44! + ...
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