Physics · Quantum Mechanics
किसी क्वांटम निकाय का तरंग फलन (wave function) -∞ < x < +∞ के लिए ψ(x) = Ne-ax2 द्वारा दिया गया है, जहाँ N सामान्यीकरण नियतांक (normalization constant) है और a एक धनात्मक वास्तविक नियतांक है। यह देखते हुए कि ∫-∞+∞e-ax2dx = √π√a है, N का मान क्या है?
- 11/(√πa)
- 2(a/2π)1/4
- 3(2a/π)1/4
- 4(a/π)1/4✓
सही उत्तर देखें
(a/π)1/4
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Preparing for Physics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Want more practice questions on Quantum Mechanics?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Physics · Quantum Mechanics