Mathematics · Three Dimensional Geometry
एक समतल π बिंदुओं (5,1,2), (3,-4,6), और (7,0,-1) से होकर गुजरता है। यदि मूल बिंदु (origin) से समतल π की लंबवत दूरी p है और l, m, n समतल π के अभिलंब की दिक-कोज्याएँ हैं, तो |3l + 2m + 5n| बराबर है:
- 1p2
- 2p✓
- 32p
- 43p
सही उत्तर देखें
p
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