Physics · Gravitation
एक युग्मतारा प्रणाली (binary star system) पर विचार करें जिसमें तारा A और तारा B जिनका द्रव्यमान क्रमशः mA और mB है, अपने उभयनिष्ठ द्रव्यमान केंद्र के चारों ओर क्रमशः rA और rB त्रिज्या की वृत्ताकार कक्षाओं में घूम रहे हैं। यदि TA और TB क्रमशः तारा A और तारा B के आवर्तकाल हैं, तो:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1TA > TB (यदि rA > rB)
- 2TA > TB (यदि mA > mB)
- 3TA = TB✓
- 4TATB = (rArB)3/2
सही उत्तर देखें
TA = TB
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