Chemistry · Thermodynamics
ऊष्मागतिक प्रक्रम के लिए निम्नलिखित में से कौन सा व्यंजक गलत है?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
Share:
- 1ΔG = ΔH - TΔS
- 2ΔG° = ΔH° - TΔS°
- 3एक उत्क्रमणीय समतापी प्रक्रम में, Wreversible = -nRT lnV2V1
- 4ΔG = -TΔS✓
सही उत्तर देखें
ΔG = -TΔS
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
👥
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Online Test Series
Start Free Mock Test →Preparing for Chemistry?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Chapter Practice
Practice Thermodynamics MCQs →Want more practice questions on Thermodynamics?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Chemistry · Thermodynamics