Mathematics · Hyperbola
अतिपरवलय (hyperbola) x2a2 - y2b2 = 1 के बिंदु 'θ' पर अभिलंब (normal) का समीकरण है:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1xa sec(θ) - yb tan(θ) = 1
- 2axsin(θ) - bycos(θ) = a2 + b2
- 3axsec(θ) + bytan(θ) = a2 + b2✓
- 4axsec(θ) - bytan(θ) = a2 - b2
सही उत्तर देखें
axsec(θ) + bytan(θ) = a2 + b2
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