Mathematics · Transformation of Axes
अक्षों को मूल बिंदु के परितः वामावर्त (counter-clockwise) दिशा में एक निश्चित कोण से घुमाने पर, यदि समीकरण x2 + 4xy + y2 = 1 बदलकर X2a2 - Y2b2 = 1 हो जाता है, तो √(a2 + b2)a2 का मान है:
- 1√10
- 232
- 3√133
- 42✓
सही उत्तर देखें
2
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