Physics · Battery Efficiency
Why is the watt-hour (ηwh) efficiency of a secondary cell always lower than its ampere-hour (ηAh) efficiency?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1Because total discharge time exceeds charging time
- 2Because terminal voltage during discharge is lower than during charging due to internal resistance✓
- 3Because energy loss during charging is zero
- 4Because the discharge current is much higher than the charging current
Correct answer
Because terminal voltage during discharge is lower than during charging due to internal resistance
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