Chemistry · Haloalkanes and Reaction Mechanisms
Why does the presence of oxygen decrease the rate of chlorination of methane in the presence of sunlight?
- 1CH3-O• free radical is formed
- 2CH3-O-Cl is formed
- 3CH3-O-O• free radical is formed✓
- 4CH3-O-•CH2 free radical is formed
Correct answer
CH3-O-O• free radical is formed
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Preparing for Chemistry?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Want more practice questions on Haloalkanes and Reaction Mechanisms?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Chemistry · Haloalkanes and Reaction Mechanisms