Chemistry · Chemical Reactions and Equations
When lead nitrate reacts with potassium iodide, a yellow precipitate of compound 'X' is formed. Identify compound X.
- 1Lead(II) iodide (PbI 2 )✓
- 2Lead(II) nitrate [Pb(NO 3 ) 2 ]
- 3Lead(II) nitrite [Pb(NO 2 ) 2 ]
- 4Potassium nitrate (KNO 3 )
Correct answer
Lead(II) iodide (PbI 2 )
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