Physics · Waves
When a stretched wire of fundamental frequency f is divided into three segments, the fundamental frequencies of these three segments are f 1 , f 2 , and f 3 , respectively. If the tension remains constant, then the relation among f, f 1 , f 2 , and f 3 is:
- 11 √f = 1 √f 1 + 1 √f 2 + 1 √f 3
- 21 f = 1 f 1 + 1 f 2 + 1 f 3✓
- 3f 1/2 = f 1 1/2 + f 2 1/2 + f 3 1/2
- 4f = f 1 + f 2 + f 3
Correct answer
1 f = 1 f 1 + 1 f 2 + 1 f 3
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