Mathematics · Definite Integration
What is wrong with the following definite integral calculation? 3-1 ∫ (1/x2) dx = -4/3
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1f(x) = 1/x2 is a continuous function on [-1, 3]
- 2The Fundamental Theorem of Calculus applies freely to discontinuous functions.
- 3The value of the integral as written does not exist, since f(x) = 1/x2 has an infinite discontinuity at x = 0.✓
- 4f(x) = 1/x2 < 0 for all x in the interval.
Correct answer
The value of the integral as written does not exist, since f(x) = 1/x2 has an infinite discontinuity at x = 0.
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