Mathematics · Differential Equations
What is the particular solution of the differential equation xy dydx = x2 + 2y2 given the initial condition y(1) = 0?
- 1x2 + 2y2 = x4
- 2x2 + y2 = x4✓
- 3x2 + y2 = x
- 4x2 + y2x3 = 1
Correct answer
x2 + y2 = x4
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