Computer · Fluid Mechanics
What is the condition for maximum velocity of flow through a circular channel section of diameter 'd' and radius 'R' (where θ is the half-central angle)?
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1Depth of flow h = 0.81d; Area of flow = R2/2 · (2θ - sin θ)
- 2Depth of flow h = 0.81d; Area of flow = R2/2 · (2θ - sin 2θ)✓
- 3Depth of flow h = 0.81d; Area of flow = R2/2 · (2 - sin 2θ)
- 4Depth of flow h = 0.81d; Area of flow = R2/2 · (θ - sin 2θ)
Correct answer
Depth of flow h = 0.81d; Area of flow = R2/2 · (2θ - sin 2θ)
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