Mathematics · Simple Harmonic Motion
Under the action of restoring force F1, a body oscillates with a time period T1, and under another force F2, it oscillates with period T2. If both forces act simultaneously in the same direction, what is the resultant time period T (assuming the displacement is the same in all cases)?
- 1T = √(T12 + T22)
- 2T = T1T2
- 3T = T1T2√(T12 + T22)✓
- 4T = √(T12 + T22)T1T2
Correct answer
T = T1T2√(T12 + T22)
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Preparing for Mathematics?
Practice full-length Mathematics mock tests with real exam timers, instant score analysis, and all-India ranking.
Want more practice questions on Simple Harmonic Motion?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Mathematics · Simple Harmonic Motion