Physics · Electrostatics
Two point charges separated by a distance r in vacuum exert a force F on each other. If these charges are placed in a medium of relative permittivity 4 and the distance between them is reduced to r2, the new force between them will be:
- 1F4
- 24F
- 3F✓
- 4F2
Correct answer
F
Download Single Question PDF
Save this question and verified answer as a clean study sheet with live clickable link.
Share with Friends & Study Groups
Challenge your peer aspirants on WhatsApp or Telegram to solve this question!
Preparing for Physics?
Practice full-length mock tests with real exam timers, instant score analysis, and all-India ranking.
Want more practice questions on Electrostatics?
Solve complete topic-wise tests with detailed solutions on GkGet.
Related Practice Questions
Recommended practice questions in Physics · Electrostatics