Physics · Special Relativity
Two events E1 and E2 take place in an inertial frame S with respective spacetime coordinates (in SI units): E1(t1 = 0, r1 = 0) and E2(t2 = 0, x2 = 108, y2 = 0, z2 = 0). Another inertial frame S' is moving with respect to S with a velocity v = 0.6c i. The time difference (t'2 - t'1) as observed in S' is:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1-0.25 s✓
- 20.25 s
- 3-0.42 s
- 40.42 s
Correct answer
-0.25 s
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