Physics · Electrostatics
Two dielectric slabs having dielectric constants K1 and K2 and thicknesses d4 and 3d4 are inserted between the plates of a capacitor of plate separation d and area A. The net capacitance of the system is (ε0 is the permittivity of free space):
- 12Aε0d × K1K23K1 + K2
- 23Aε0d × K1 + K2K1K2
- 33Aε02d × K1 + K2K1K2
- 44Aε0d × K1K23K1 + K2✓
Correct answer
4Aε0d × K1K23K1 + K2
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