Mathematics · Probability
Two dice are thrown independently. Let A be the event that the number appearing on the 1st die is less than the number appearing on the 2nd die, B be the event that the number appearing on the 1st die is even and that on the 2nd die is odd, and C be the event that the number appearing on the 1st die is odd and that on the 2nd die is even. Then:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1B and C are independent
- 2the number of favorable cases of the events A, B and C are 15, 6 and 6 respectively
- 3A and B are mutually exclusive
- 4the number of favorable cases of the event (A ∪ B) ∩ C is 6✓
Correct answer
the number of favorable cases of the event (A ∪ B) ∩ C is 6
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