Mathematics · Speed, Time and Distance
Three drones (A, B, and C) are flown across a 360-meter-long testing course. The time taken by drone A is 't' seconds, by drone B is '(t + 4)' seconds, and by drone C is '(t - 2)' seconds. The speed of drone A is 20% more than that of drone B. The speed of drone C is 2 m/s more than that of drone A. Quantity I: If the speed of drone B were ___% of its original speed, it would have crossed the course in 30 seconds. Quantity II: If the speed of drone C were ___% of its original speed, it would have crossed the course in 24 seconds.
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1Quantity I ≤ Quantity II
- 2Quantity I ≥ Quantity II
- 3Quantity I < Quantity II
- 4Quantity I > Quantity II✓
Correct answer
Quantity I > Quantity II
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