Mathematics · Vector Algebra
The vector equation of a line passing through the points (3, 4, -7) and (1, -1, 6) is given by:
- 1r = (-2i - 5j + 13k) + λ(3i + 4j - 7k)
- 2r = (3i + 4j - 7k) + λ(4i + 3j - k)
- 3r = (i - j + 6k) + λ(3i + 4j - 7k)
- 4r = (3i + 4j - 7k) + λ(-2i - 5j + 13k)✓
Correct answer
r = (3i + 4j - 7k) + λ(-2i - 5j + 13k)
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