Mathematics · Calculus
The value of the integral ∫ (u(d2v/dx2) - v(d2u/dx2)) dx is:
- 1dv/dx + du/dx
- 2u(dv/dx) - v(du/dx)✓
- 3u(dv/dx) + v(du/dx)
- 4dv/dx - du/dx
Correct answer
u(dv/dx) - v(du/dx)
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