Mathematics · Limits
The value of limx→0 loge (sec(ex) · sec(e2x) ··· sec(e10x))e2 − e2 cos x is equal to:
Verified Solution4 OptionsUpdated: October 2026👁️1 View
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- 1e10 − 12e2(e2 − 1)
- 2e20 − 12e2(e2 − 1)✓
- 3e20 − 12(e2 − 1)
- 4e10 − 12(e2 − 1)
Correct answer
e20 − 12e2(e2 − 1)
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