Mathematics · Vector Calculus

The unit normal to the surface x2 + 4y2 - 3z2 - 2 = 0 at the point (1, 1, 1) is:

Verified Solution4 OptionsUpdated: October 2026👁️1 View

11√11(i - 3j - k)
21√3(i + j + k)
3i + 4j - 3k
41√26(i + 4j - 3k)✓

Correct answer

1√26(i + 4j - 3k)

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The unit normal to the surface x2 + 4y2 - 3z2 - 2 = 0 at the point (1, 1, 1) is:

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