Mathematics · Recurrence Relations
The solution to the recurrence relation: P(n) = 1, for n = 1 P(n) = n-1∑k=1 P(k)P(n-k), for n ≥ 2 is:
- 1O(n2)
- 2O(n4)
- 3Ω(n3)
- 4Ω(2n)✓
Correct answer
Ω(2n)
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