Mathematics · Differential Equations
The solution to Legendre's linear differential equation (3x + 2)2d2ydx2 + 3(3x + 2)dydx - 36y = 3x2 + 4x + 1 is:
- 1y = C1(3x + 2)2 + C2(3x + 2)-2 - 1108 [(3x + 2)2 log(3x + 2) + 1]
- 2y = C1(3x + 2)2 + C2(3x + 2)-2 + 1108 [(3x + 2)2 log(3x + 2) + 1]✓
- 3y = C1(3x - 2)2 + C2(3x + 2)-2 + 1108 [(3x + 2)2 log(3x + 2) + 1]
- 4y = C1(3x - 2)2 + C2(3x + 2)-2 - 1108 [(3x + 2)2 log(3x + 2) + 1]
Correct answer
y = C1(3x + 2)2 + C2(3x + 2)-2 + 1108 [(3x + 2)2 log(3x + 2) + 1]
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